5-2100x^2=0

Solution for 5-2100x^2=0 equation:

5-2100x^2=0

a = -2100; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-2100)·5
Δ = 42000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{42000}=\sqrt{400*105}=\sqrt{400}*\sqrt{105}=20\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{105}}{2*-2100}=\frac{0-20\sqrt{105}}{-4200}
=-\frac{20\sqrt{105}}{-4200}
=-\frac{\sqrt{105}}{-210}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{105}}{2*-2100}=\frac{0+20\sqrt{105}}{-4200}
=\frac{20\sqrt{105}}{-4200}
=\frac{\sqrt{105}}{-210}
$